यदि चाप की लंबाई \(\frac{9\pi}{2}\) सेमी और त्रिज्या (12) सेमी है, तो केंद्र कोण डिग्री में कितना होगा?
If the arc length is \(\frac{9\pi}{2}\) cm and the radius is (12) cm, what is the central angle in degrees?
Explanation opens after your attempt
Correct Answer
C. \(67.5^\circ\)
Step 1
Concept
From \(s=r\theta\), \(\theta=\frac{3\pi}{8}\), which is \(67.5^\circ\). In exams, keep the angle in radians in the arc formula.
Step 2
Why this answer is correct
The correct answer is C. \(67.5^\circ\). From \(s=r\theta\), \(\theta=\frac{3\pi}{8}\), which is \(67.5^\circ\). In exams, keep the angle in radians in the arc formula.
Step 3
Exam Tip
\(s=r\theta\) से \(\theta=\frac{3\pi}{8}\), जो \(67.5^\circ\) है। परीक्षा में चाप सूत्र में कोण रेडियन में रखें।
Mathematics Answer, Explanation and Revision Hints
यदि चाप की लंबाई \(\frac{9\pi}{2}\) सेमी और त्रिज्या (12) सेमी है, तो केंद्र कोण डिग्री में कितना होगा? / If the arc length is \(\frac{9\pi}{2}\) cm and the radius is (12) cm, what is the central angle in degrees?
Correct Answer: C. \(67.5^\circ\). Explanation: \(s=r\theta\) से \(\theta=\frac{3\pi}{8}\), जो \(67.5^\circ\) है। परीक्षा में चाप सूत्र में कोण रेडियन में रखें। / From \(s=r\theta\), \(\theta=\frac{3\pi}{8}\), which is \(67.5^\circ\). In exams, keep the angle in radians in the arc formula.
Which concept should I revise for this Mathematics MCQ?
From \(s=r\theta\), \(\theta=\frac{3\pi}{8}\), which is \(67.5^\circ\). In exams, keep the angle in radians in the arc formula.
What exam hint can help solve this Mathematics question?
\(s=r\theta\) से \(\theta=\frac{3\pi}{8}\), जो \(67.5^\circ\) है। परीक्षा में चाप सूत्र में कोण रेडियन में रखें।
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