Hard Mathematics Polynomials Class 10 Level 27

यदि (p(x)=x-2-\(\sqrt{2}+\sqrt{3}\)x+\sqrt{6}), तो शून्यक कौन से हैं?

If (p(x)=x-2-\(\sqrt{2}+\sqrt{3}\)x+\sqrt{6}), what are the zeroes?

Explanation opens after your attempt
Correct Answer

A. \(\sqrt{2}\) और \(\sqrt{3}\)\(\sqrt{2}\) and \(\sqrt{3}\)

Step 1

Concept

The sum is \(\sqrt{2}+\sqrt{3}\) and the product is \(\sqrt{6}\). These match \(\sqrt{2}\) and \(\sqrt{3}\).

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{2}\) और \(\sqrt{3}\) / \(\sqrt{2}\) and \(\sqrt{3}\). The sum is \(\sqrt{2}+\sqrt{3}\) and the product is \(\sqrt{6}\). These match \(\sqrt{2}\) and \(\sqrt{3}\).

Step 3

Exam Tip

योग \(\sqrt{2}+\sqrt{3}\) और गुणनफल \(\sqrt{6}\) है। ये \(\sqrt{2}\) और \(\sqrt{3}\) से मिलते हैं।

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Mathematics Answer, Explanation and Revision Hints

यदि (p(x)=x-2-\(\sqrt{2}+\sqrt{3}\)x+\sqrt{6}), तो शून्यक कौन से हैं? / If (p(x)=x-2-\(\sqrt{2}+\sqrt{3}\)x+\sqrt{6}), what are the zeroes?

Correct Answer: A. \(\sqrt{2}\) और \(\sqrt{3}\) / \(\sqrt{2}\) and \(\sqrt{3}\). Explanation: योग \(\sqrt{2}+\sqrt{3}\) और गुणनफल \(\sqrt{6}\) है। ये \(\sqrt{2}\) और \(\sqrt{3}\) से मिलते हैं। / The sum is \(\sqrt{2}+\sqrt{3}\) and the product is \(\sqrt{6}\). These match \(\sqrt{2}\) and \(\sqrt{3}\).

Which concept should I revise for this Mathematics MCQ?

The sum is \(\sqrt{2}+\sqrt{3}\) and the product is \(\sqrt{6}\). These match \(\sqrt{2}\) and \(\sqrt{3}\).

What exam hint can help solve this Mathematics question?

योग \(\sqrt{2}+\sqrt{3}\) और गुणनफल \(\sqrt{6}\) है। ये \(\sqrt{2}\) और \(\sqrt{3}\) से मिलते हैं।

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