यदि (p(x)=x-2+cx+c-2) और \(c\neq0\), तो ग्राफ (x)-अक्ष को क्यों नहीं काटेगा?
If (p(x)=x-2+cx+c-2) and \(c\neq0\), why will the graph not cut the (x)-axis?
Explanation opens after your attempt
Correct Answer
A. क्योंकि इसका विविक्तकर ऋणात्मक हैBecause its discriminant is negative
Concept
The discriminant is \(c^2-4c^2=-3c^2<0\), so there are no real zeroes. Tip: a negative discriminant means no (x)-axis intersection.
Why this answer is correct
The correct answer is A. क्योंकि इसका विविक्तकर ऋणात्मक है / Because its discriminant is negative. The discriminant is \(c^2-4c^2=-3c^2<0\), so there are no real zeroes. Tip: a negative discriminant means no (x)-axis intersection.
Exam Tip
विविक्तकर \(c^2-4c^2=-3c^2<0\) है, इसलिए वास्तविक शून्यक नहीं हैं। टिप: ऋणात्मक विविक्तकर का अर्थ (x)-अक्ष कटान नहीं है।
Login to save your score, XP, coins and progress.