Hard Mathematics Polynomials Class 10 Level 28

यदि (p(x)=x-2-7) है, तो (p\(\sqrt{7}+1\)) का मान किस रूप में है?

If (p(x)=x-2-7), what is the form of (p\(\sqrt{7}+1\))?

Explanation opens after your attempt
Correct Answer

A. \(1+2\sqrt{7}\)

Step 1

Concept

(\(\sqrt{7}+1\)2-7=8+2\sqrt{7}-7=1+2\sqrt{7}). Use ((a+b)2) carefully in exams.

Step 2

Why this answer is correct

The correct answer is A. \(1+2\sqrt{7}\). (\(\sqrt{7}+1\)2-7=8+2\sqrt{7}-7=1+2\sqrt{7}). Use ((a+b)2) carefully in exams.

Step 3

Exam Tip

(\(\sqrt{7}+1\)2-7=8+2\sqrt{7}-7=1+2\sqrt{7}) है। परीक्षा में ((a+b)2) सावधानी से लगाएं।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि (p(x)=x-2-7) है, तो (p\(\sqrt{7}+1\)) का मान किस रूप में है? / If (p(x)=x-2-7), what is the form of (p\(\sqrt{7}+1\))?

Correct Answer: A. \(1+2\sqrt{7}\). Explanation: (\(\sqrt{7}+1\)2-7=8+2\sqrt{7}-7=1+2\sqrt{7}) है। परीक्षा में ((a+b)2) सावधानी से लगाएं। / (\(\sqrt{7}+1\)2-7=8+2\sqrt{7}-7=1+2\sqrt{7}). Use ((a+b)2) carefully in exams.

Which concept should I revise for this Mathematics MCQ?

(\(\sqrt{7}+1\)2-7=8+2\sqrt{7}-7=1+2\sqrt{7}). Use ((a+b)2) carefully in exams.

What exam hint can help solve this Mathematics question?

(\(\sqrt{7}+1\)2-7=8+2\sqrt{7}-7=1+2\sqrt{7}) है। परीक्षा में ((a+b)2) सावधानी से लगाएं।

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