Hard Mathematics Polynomials Class 10 Level 26

यदि (p(x)=x-2-4\sqrt{2}x+8), तो यह किस रूप में लिखा जा सकता है?

If (p(x)=x-2-4\sqrt{2}x+8), in which form can it be written?

Explanation opens after your attempt
Correct Answer

A. (\(x-2\sqrt{2}\)2)

Step 1

Concept

Because (\(2\sqrt{2}\)2=8) and the middle term is \(-4\sqrt{2}x\). Hence it is a perfect square.

Step 2

Why this answer is correct

The correct answer is A. (\(x-2\sqrt{2}\)2). Because (\(2\sqrt{2}\)2=8) and the middle term is \(-4\sqrt{2}x\). Hence it is a perfect square.

Step 3

Exam Tip

क्योंकि (\(2\sqrt{2}\)2=8) और बीच का पद \(-4\sqrt{2}x\) है। अतः यह पूर्ण वर्ग है।

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Mathematics Answer, Explanation and Revision Hints

यदि (p(x)=x-2-4\sqrt{2}x+8), तो यह किस रूप में लिखा जा सकता है? / If (p(x)=x-2-4\sqrt{2}x+8), in which form can it be written?

Correct Answer: A. (\(x-2\sqrt{2}\)2). Explanation: क्योंकि (\(2\sqrt{2}\)2=8) और बीच का पद \(-4\sqrt{2}x\) है। अतः यह पूर्ण वर्ग है। / Because (\(2\sqrt{2}\)2=8) and the middle term is \(-4\sqrt{2}x\). Hence it is a perfect square.

Which concept should I revise for this Mathematics MCQ?

Because (\(2\sqrt{2}\)2=8) and the middle term is \(-4\sqrt{2}x\). Hence it is a perfect square.

What exam hint can help solve this Mathematics question?

क्योंकि (\(2\sqrt{2}\)2=8) और बीच का पद \(-4\sqrt{2}x\) है। अतः यह पूर्ण वर्ग है।

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