Hard Mathematics Polynomials Class 10 Level 22

यदि (p(x)=x-2-2x+5), तो (p(x)=0) का ग्राफीय अर्थ क्या होगा?

If (p(x)=x-2-2x+5), what will be the graphical meaning of (p(x)=0)?

Explanation opens after your attempt
Correct Answer

C. ग्राफ (x)-अक्ष को नहीं काटताThe graph does not cut the (x)-axis

Step 1

Concept

(x-2-2x+5=(x-1)2+4), so it cannot be zero for real (x). Tip: an always positive form gives no real intersection.

Step 2

Why this answer is correct

The correct answer is C. ग्राफ (x)-अक्ष को नहीं काटता / The graph does not cut the (x)-axis. (x-2-2x+5=(x-1)2+4), so it cannot be zero for real (x). Tip: an always positive form gives no real intersection.

Step 3

Exam Tip

(x-2-2x+5=(x-1)2+4) है, इसलिए वास्तविक (x) पर शून्य नहीं बनेगा। टिप: हमेशा धनात्मक रूप कोई वास्तविक कटान नहीं देता।

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Mathematics Answer, Explanation and Revision Hints

यदि (p(x)=x-2-2x+5), तो (p(x)=0) का ग्राफीय अर्थ क्या होगा? / If (p(x)=x-2-2x+5), what will be the graphical meaning of (p(x)=0)?

Correct Answer: C. ग्राफ (x)-अक्ष को नहीं काटता / The graph does not cut the (x)-axis. Explanation: (x-2-2x+5=(x-1)2+4) है, इसलिए वास्तविक (x) पर शून्य नहीं बनेगा। टिप: हमेशा धनात्मक रूप कोई वास्तविक कटान नहीं देता। / (x-2-2x+5=(x-1)2+4), so it cannot be zero for real (x). Tip: an always positive form gives no real intersection.

Which concept should I revise for this Mathematics MCQ?

(x-2-2x+5=(x-1)2+4), so it cannot be zero for real (x). Tip: an always positive form gives no real intersection.

What exam hint can help solve this Mathematics question?

(x-2-2x+5=(x-1)2+4) है, इसलिए वास्तविक (x) पर शून्य नहीं बनेगा। टिप: हमेशा धनात्मक रूप कोई वास्तविक कटान नहीं देता।

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