Expert Mathematics Polynomials Class 10 Level 25

यदि (p(x)=x-2+2\sqrt{7}x+6), तो इसके शून्यक कौन से हैं?

If (p(x)=x-2+2\sqrt{7}x+6), what are its zeroes?

Explanation opens after your attempt
Correct Answer

A. \(-\sqrt{7}+1\) और \(-\sqrt{7}-1\)\(-\sqrt{7}+1\) and \(-\sqrt{7}-1\)

Step 1

Concept

Using the formula, \(x=\frac{-2\sqrt{7}\pm2}{2}=-\sqrt{7}\pm1\). Simplifying the discriminant first gives a clean answer.

Step 2

Why this answer is correct

The correct answer is A. \(-\sqrt{7}+1\) और \(-\sqrt{7}-1\) / \(-\sqrt{7}+1\) and \(-\sqrt{7}-1\). Using the formula, \(x=\frac{-2\sqrt{7}\pm2}{2}=-\sqrt{7}\pm1\). Simplifying the discriminant first gives a clean answer.

Step 3

Exam Tip

सूत्र से \(x=\frac{-2\sqrt{7}\pm2}{2}=-\sqrt{7}\pm1\)। पहले विविक्तकर सरल करने से उत्तर साफ मिलता है।

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Mathematics Answer, Explanation and Revision Hints

यदि (p(x)=x-2+2\sqrt{7}x+6), तो इसके शून्यक कौन से हैं? / If (p(x)=x-2+2\sqrt{7}x+6), what are its zeroes?

Correct Answer: A. \(-\sqrt{7}+1\) और \(-\sqrt{7}-1\) / \(-\sqrt{7}+1\) and \(-\sqrt{7}-1\). Explanation: सूत्र से \(x=\frac{-2\sqrt{7}\pm2}{2}=-\sqrt{7}\pm1\)। पहले विविक्तकर सरल करने से उत्तर साफ मिलता है। / Using the formula, \(x=\frac{-2\sqrt{7}\pm2}{2}=-\sqrt{7}\pm1\). Simplifying the discriminant first gives a clean answer.

Which concept should I revise for this Mathematics MCQ?

Using the formula, \(x=\frac{-2\sqrt{7}\pm2}{2}=-\sqrt{7}\pm1\). Simplifying the discriminant first gives a clean answer.

What exam hint can help solve this Mathematics question?

सूत्र से \(x=\frac{-2\sqrt{7}\pm2}{2}=-\sqrt{7}\pm1\)। पहले विविक्तकर सरल करने से उत्तर साफ मिलता है।

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