यदि (p(x)=x-2-12x+31), तो शून्यकों के बीच का अंतर क्या है?
If (p(x)=x-2-12x+31), what is the difference between its zeroes?
Explanation opens after your attempt
Correct Answer
A. \(2\sqrt{5}\)
Concept
The zeroes are \(6\pm\sqrt{5}\), so the difference is \(2\sqrt{5}\). The difference of conjugate zeroes is (2) times the radical part.
Why this answer is correct
The correct answer is A. \(2\sqrt{5}\). The zeroes are \(6\pm\sqrt{5}\), so the difference is \(2\sqrt{5}\). The difference of conjugate zeroes is (2) times the radical part.
Exam Tip
शून्यक \(6\pm\sqrt{5}\) हैं, इसलिए अंतर \(2\sqrt{5}\) है। संयुग्मी शून्यकों का अंतर (2) गुणा मूल पद होता है।
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