यदि (p(x)=x-2-10x+29) है, तो ग्राफ (x)-अक्ष को क्यों नहीं काटेगा?
If (p(x)=x-2-10x+29), why will the graph not cut the (x)-axis?
Explanation opens after your attempt
Correct Answer
A. क्योंकि यह ((x-5)2+4) हैBecause it is ((x-5)2+4)
Concept
((x-5)2+4) is always positive, so (p(x)=0) will not occur. Tip: adding a positive number to a square gives no real intersection.
Why this answer is correct
The correct answer is A. क्योंकि यह ((x-5)2+4) है / Because it is ((x-5)2+4). ((x-5)2+4) is always positive, so (p(x)=0) will not occur. Tip: adding a positive number to a square gives no real intersection.
Exam Tip
((x-5)2+4) हमेशा धनात्मक है, इसलिए (p(x)=0) नहीं होगा। टिप: वर्ग में धनात्मक संख्या जुड़ने पर वास्तविक कटान नहीं मिलता।
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