यदि (p(x)=(x+1)2(x-8)2) है तो ग्राफ (x)-अक्ष के साथ कैसा व्यवहार करेगा?
If (p(x)=(x+1)2(x-8)2), how will the graph behave with the (x)-axis?
Explanation opens after your attempt
B. दोनों शून्यकों पर स्पर्श करेगाIt will touch at both zeroes
Concept
Both factors have even powers, so the graph touches at both places. Tip: an even-power zero usually gives touching, not crossing.
Why this answer is correct
The correct answer is B. दोनों शून्यकों पर स्पर्श करेगा / It will touch at both zeroes. Both factors have even powers, so the graph touches at both places. Tip: an even-power zero usually gives touching, not crossing.
Exam Tip
दोनों कारक सम घात में हैं इसलिए दोनों स्थानों पर स्पर्श होगा। टिप: सम घात वाला शून्यक सामान्यतः कटान नहीं बल्कि स्पर्श देता है।
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