यदि (p(x)=9x-2-16) है, तो ग्राफ के (x)-अक्ष कटान कौन से हैं?
If (p(x)=9x-2-16), what are the (x)-axis intersections of the graph?
Explanation opens after your attempt
Correct Answer
A. (\left\(\frac{4}{3},0\right\)) और (\left\(-\frac{4}{3},0\right\))(\left\(\frac{4}{3},0\right\)) and (\left\(-\frac{4}{3},0\right\))
Concept
From \(9x^2-16=0\), \(x=\pm\frac{4}{3}\). Tip: treat \(9x^2\) as ((3x)2).
Why this answer is correct
The correct answer is A. (\left\(\frac{4}{3},0\right\)) और (\left\(-\frac{4}{3},0\right\)) / (\left\(\frac{4}{3},0\right\)) and (\left\(-\frac{4}{3},0\right\)). From \(9x^2-16=0\), \(x=\pm\frac{4}{3}\). Tip: treat \(9x^2\) as ((3x)2).
Exam Tip
\(9x^2-16=0\) से \(x=\pm\frac{4}{3}\) मिलता है। टिप: \(9x^2\) को ((3x)2) समझें।
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