यदि (p(x)=25x-2-36) है, तो ग्राफ के (x)-अक्ष कटान कौन से हैं?
If (p(x)=25x-2-36), what are the (x)-axis intersections of the graph?
Explanation opens after your attempt
Correct Answer
A. (\left\(\frac{6}{5},0\right\)) और (\left\(-\frac{6}{5},0\right\))(\left\(\frac{6}{5},0\right\)) and (\left\(-\frac{6}{5},0\right\))
Concept
From \(25x^2-36=0\), \(x=\pm\frac{6}{5}\). Tip: treat \(25x^2\) as ((5x)2).
Why this answer is correct
The correct answer is A. (\left\(\frac{6}{5},0\right\)) और (\left\(-\frac{6}{5},0\right\)) / (\left\(\frac{6}{5},0\right\)) and (\left\(-\frac{6}{5},0\right\)). From \(25x^2-36=0\), \(x=\pm\frac{6}{5}\). Tip: treat \(25x^2\) as ((5x)2).
Exam Tip
\(25x^2-36=0\) से \(x=\pm\frac{6}{5}\) मिलता है। टिप: \(25x^2\) को ((5x)2) समझें।
Login to save your score, XP, coins and progress.