यदि (x-2-(m-2)x+m-6=0) की एक जड़ (3) है, तो दूसरी जड़ क्या होगी?
If one root of (x-2-(m-2)x+m-6=0) is (3), what is the other root?
Explanation opens after your attempt
Correct Answer
A. (1)
Concept
Putting (x=3) gives (9-3(m-2)+m-6=0), so \(m=\frac{9}{2}\). The product is \(-\frac{3}{2}\), so the other root is \(-\frac{1}{2}\); hence no option is correct.
Why this answer is correct
The correct answer is A. (1). Putting (x=3) gives (9-3(m-2)+m-6=0), so \(m=\frac{9}{2}\). The product is \(-\frac{3}{2}\), so the other root is \(-\frac{1}{2}\); hence no option is correct.
Exam Tip
(x=3) रखने पर (9-3(m-2)+m-6=0), इसलिए \(m=\frac{9}{2}\)। गुणनफल \(m-6=-\frac{3}{2}\) है, अतः दूसरी जड़ \(-\frac{1}{2}\) होगी, इसलिए कोई विकल्प सही नहीं है।
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