Expert Mathematics Polynomials Class 10 Level 26

यदि \(\frac{35}{2^2\cdot5\cdot7^2}\) को सरलतम रूप में लिखा जाए, तो उसका दशमलव प्रसार कैसा होगा?

If \(\frac{35}{2^2\cdot5\cdot7^2}\) is written in lowest form, what type of decimal expansion will it have?

Explanation opens after your attempt
Correct Answer

A. अनवसानी आवर्तीNon-terminating recurring

Step 1

Concept

After simplification, (7) remains in the denominator, so the decimal is non-terminating recurring. In exams do not decide only from the original denominator.

Step 2

Why this answer is correct

The correct answer is A. अनवसानी आवर्ती / Non-terminating recurring. After simplification, (7) remains in the denominator, so the decimal is non-terminating recurring. In exams do not decide only from the original denominator.

Step 3

Exam Tip

सरलीकरण के बाद हर में (7) बचता है, इसलिए दशमलव अनवसानी आवर्ती होगा। परीक्षा में केवल मूल हर देखकर निर्णय न लें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(\frac{35}{2^2\cdot5\cdot7^2}\) को सरलतम रूप में लिखा जाए, तो उसका दशमलव प्रसार कैसा होगा? / If \(\frac{35}{2^2\cdot5\cdot7^2}\) is written in lowest form, what type of decimal expansion will it have?

Correct Answer: A. अनवसानी आवर्ती / Non-terminating recurring. Explanation: सरलीकरण के बाद हर में (7) बचता है, इसलिए दशमलव अनवसानी आवर्ती होगा। परीक्षा में केवल मूल हर देखकर निर्णय न लें। / After simplification, (7) remains in the denominator, so the decimal is non-terminating recurring. In exams do not decide only from the original denominator.

Which concept should I revise for this Mathematics MCQ?

After simplification, (7) remains in the denominator, so the decimal is non-terminating recurring. In exams do not decide only from the original denominator.

What exam hint can help solve this Mathematics question?

सरलीकरण के बाद हर में (7) बचता है, इसलिए दशमलव अनवसानी आवर्ती होगा। परीक्षा में केवल मूल हर देखकर निर्णय न लें।

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