समीकरण \(x^2+px+36=0\) के दोनों मूल (-6) और (-6) हैं तो (p) का मान क्या है?
If both roots of \(x^2+px+36=0\) are (-6) and (-6), what is the value of (p)?
Explanation opens after your attempt
A. (12)
Concept
The sum of roots is (-12), and (-p=-12). Therefore (p=12).
Why this answer is correct
The correct answer is A. (12). The sum of roots is (-12), and (-p=-12). Therefore (p=12).
Exam Tip
मूलों का योग (-12) है और (-p=-12) होगा। इसलिए (p=12) है।
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