यदि समीकरण \(x^2+bx+64=0\) के दोनों मूल समान हैं और उनका मान (-8) है, तो (b) क्या है?
If both roots of \(x^2+bx+64=0\) are equal and their value is (-8), what is (b)?
Explanation opens after your attempt
Correct Answer
A. (16)
Concept
Both roots are (-8), so the sum is (-16). Here the sum of roots is (-b), so (b=16).
Why this answer is correct
The correct answer is A. (16). Both roots are (-8), so the sum is (-16). Here the sum of roots is (-b), so (b=16).
Exam Tip
दोनों मूल (-8) हैं, इसलिए योग (-16) है। यहाँ मूलों का योग (-b) है, अतः (b=16)।
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