यदि समीकरण \(x^2+bx+49=0\) के दोनों मूल समान हैं और उनका मान (-7) है, तो (b) क्या है?
If both roots of \(x^2+bx+49=0\) are equal and their value is (-7), what is (b)?
Explanation opens after your attempt
Correct Answer
A. (14)
Concept
Both roots are (-7), so their sum is (-14). Here the sum of roots is (-b), so (b=14).
Why this answer is correct
The correct answer is A. (14). Both roots are (-7), so their sum is (-14). Here the sum of roots is (-b), so (b=14).
Exam Tip
दोनों मूल (-7) हैं, इसलिए योग (-14) है। यहाँ मूलों का योग (-b) है, अतः (b=14)।
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