यदि समीकरण \(x^2+bx+100=0\) के दोनों मूल समान हैं और उनका मान (-10) है, तो (b) क्या है?
If both roots of \(x^2+bx+100=0\) are equal and their value is (-10), what is (b)?
Explanation opens after your attempt
Correct Answer
A. (20)
Concept
Both roots are (-10), so the sum is (-20). Here the sum of roots is (-b), so (b=20).
Why this answer is correct
The correct answer is A. (20). Both roots are (-10), so the sum is (-20). Here the sum of roots is (-b), so (b=20).
Exam Tip
दोनों मूल (-10) हैं, इसलिए योग (-20) है। यहाँ मूलों का योग (-b) है, अतः (b=20)।
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