Expert Mathematics Quadratic Equations Class 10 Level 31

यदि \(x^2-6x+5=0\) की जड़ें \(\alpha,\beta\) हैं, तो \(3\alpha-2\) और \(3\beta-2\) जड़ों वाला समीकरण कौन-सा है?

If \(\alpha,\beta\) are the roots of \(x^2-6x+5=0\), which equation has roots \(3\alpha-2\) and \(3\beta-2\)?

Explanation opens after your attempt
Correct Answer

A. \(x^2-14x+13=0\)

Step 1

Concept

The original roots are (1) and (5), so the new roots are (1) and (13). Their equation is \(x^2-14x+13=0\).

Step 2

Why this answer is correct

The correct answer is A. \(x^2-14x+13=0\). The original roots are (1) and (5), so the new roots are (1) and (13). Their equation is \(x^2-14x+13=0\).

Step 3

Exam Tip

मूल जड़ें (1) और (5) हैं, इसलिए नई जड़ें (1) और (13) हैं। उनका समीकरण \(x^2-14x+13=0\) है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x^2-6x+5=0\) की जड़ें \(\alpha,\beta\) हैं, तो \(3\alpha-2\) और \(3\beta-2\) जड़ों वाला समीकरण कौन-सा है? / If \(\alpha,\beta\) are the roots of \(x^2-6x+5=0\), which equation has roots \(3\alpha-2\) and \(3\beta-2\)?

Correct Answer: A. \(x^2-14x+13=0\). Explanation: मूल जड़ें (1) और (5) हैं, इसलिए नई जड़ें (1) और (13) हैं। उनका समीकरण \(x^2-14x+13=0\) है। / The original roots are (1) and (5), so the new roots are (1) and (13). Their equation is \(x^2-14x+13=0\).

Which concept should I revise for this Mathematics MCQ?

The original roots are (1) and (5), so the new roots are (1) and (13). Their equation is \(x^2-14x+13=0\).

What exam hint can help solve this Mathematics question?

मूल जड़ें (1) और (5) हैं, इसलिए नई जड़ें (1) और (13) हैं। उनका समीकरण \(x^2-14x+13=0\) है।

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