यदि \(7x^2-25x+12=0\) के मूल \(\alpha,\beta\) हैं, तो (\(\alpha-\beta\)2) क्या होगा?
If \(\alpha,\beta\) are roots of \(7x^2-25x+12=0\), what is (\(\alpha-\beta\)2)?
Explanation opens after your attempt
Correct Answer
A. \( \frac{289}{49}\)
Concept
(\(\alpha-\beta\)2=\(\alpha+\beta\)2-4\alpha\beta=\left\(\frac{25}{7}\right\)2-\frac{48}{7}=\frac{289}{49}). In exams, convert fractions to a common denominator.
Why this answer is correct
The correct answer is A. \( \frac{289}{49}\). (\(\alpha-\beta\)2=\(\alpha+\beta\)2-4\alpha\beta=\left\(\frac{25}{7}\right\)2-\frac{48}{7}=\frac{289}{49}). In exams, convert fractions to a common denominator.
Exam Tip
(\(\alpha-\beta\)2=\(\alpha+\beta\)2-4\alpha\beta=\left\(\frac{25}{7}\right\)2-\frac{48}{7}=\frac{289}{49}) है। परीक्षा में भिन्नों को समान हर में बदलें।
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