Medium Mathematics Quadratic Equations Class 10 Level 32

यदि \(\alpha+\beta=-5\) और \(\alpha\beta=-14\) है तो \(\alpha\) और \(\beta\) के लिए मोनिक समीकरण कौन सा है?

If \(\alpha+\beta=-5\) and \(\alpha\beta=-14\), which monic equation has roots \(\alpha\) and \(\beta\)?

Explanation opens after your attempt
Correct Answer

A. \(x^2+5x-14=0\)

Step 1

Concept

The monic equation is (x-2-\(\alpha+\beta\)x+\alpha\beta=0). Therefore \(x^2+5x-14=0\) is correct.

Step 2

Why this answer is correct

The correct answer is A. \(x^2+5x-14=0\). The monic equation is (x-2-\(\alpha+\beta\)x+\alpha\beta=0). Therefore \(x^2+5x-14=0\) is correct.

Step 3

Exam Tip

मोनिक समीकरण (x-2-\(\alpha+\beta\)x+\alpha\beta=0) होता है। इसलिए \(x^2+5x-14=0\) सही है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(\alpha+\beta=-5\) और \(\alpha\beta=-14\) है तो \(\alpha\) और \(\beta\) के लिए मोनिक समीकरण कौन सा है? / If \(\alpha+\beta=-5\) and \(\alpha\beta=-14\), which monic equation has roots \(\alpha\) and \(\beta\)?

Correct Answer: A. \(x^2+5x-14=0\). Explanation: मोनिक समीकरण (x-2-\(\alpha+\beta\)x+\alpha\beta=0) होता है। इसलिए \(x^2+5x-14=0\) सही है। / The monic equation is (x-2-\(\alpha+\beta\)x+\alpha\beta=0). Therefore \(x^2+5x-14=0\) is correct.

Which concept should I revise for this Mathematics MCQ?

The monic equation is (x-2-\(\alpha+\beta\)x+\alpha\beta=0). Therefore \(x^2+5x-14=0\) is correct.

What exam hint can help solve this Mathematics question?

मोनिक समीकरण (x-2-\(\alpha+\beta\)x+\alpha\beta=0) होता है। इसलिए \(x^2+5x-14=0\) सही है।

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