यदि \(x^2-2x-11\) के शून्यक \(\alpha\) और \(\beta\) हैं, तो \(\alpha^2+\beta^2+\alpha\beta\) क्या है?
If \(\alpha\) and \(\beta\) are zeroes of \(x^2-2x-11\), what is \(\alpha^2+\beta^2+\alpha\beta\)?
Explanation opens after your attempt
Correct Answer
A. (15)
Concept
\(\alpha+\beta=2\) and \(\alpha\beta=-11\), so (\alpha-2+\beta-2+\alpha\beta=\(\alpha+\beta\)2-\alpha\beta=4+11=15). Sum and product are enough for symmetric expressions.
Why this answer is correct
The correct answer is A. (15). \(\alpha+\beta=2\) and \(\alpha\beta=-11\), so (\alpha-2+\beta-2+\alpha\beta=\(\alpha+\beta\)2-\alpha\beta=4+11=15). Sum and product are enough for symmetric expressions.
Exam Tip
\(\alpha+\beta=2\) और \(\alpha\beta=-11\), इसलिए (\alpha-2+\beta-2+\alpha\beta=\(\alpha+\beta\)2-\alpha\beta=4+11=15)। सममित व्यंजकों में योग और गुणनफल काफी होते हैं।
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