यदि \(x^2-14x+45=0\) के मूल \(\alpha\) और \(\beta\) हैं तो \(\frac{\alpha^2+\beta^2}{\alpha\beta}\) का मान क्या है?
If \(\alpha\) and \(\beta\) are roots of \(x^2-14x+45=0\), what is the value of \(\frac{\alpha^2+\beta^2}{\alpha\beta}\)?
Explanation opens after your attempt
Correct Answer
A. \(\frac{106}{45}\)
Concept
Here \(\alpha+\beta=14\) and \(\alpha\beta=45\). \(\alpha^2+\beta^2=196-90=106\), so the value is \(\frac{106}{45}\).
Why this answer is correct
The correct answer is A. \(\frac{106}{45}\). Here \(\alpha+\beta=14\) and \(\alpha\beta=45\). \(\alpha^2+\beta^2=196-90=106\), so the value is \(\frac{106}{45}\).
Exam Tip
यहां \(\alpha+\beta=14\) और \(\alpha\beta=45\) है। \(\alpha^2+\beta^2=196-90=106\) इसलिए मान \(\frac{106}{45}\) है।
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