यदि \(x^2-12x+36=0\) के मूल \(\alpha\) और \(\beta\) हैं तो \(\alpha-\beta\) का मान क्या है?
If \(\alpha\) and \(\beta\) are roots of \(x^2-12x+36=0\), what is the value of \(\alpha-\beta\)?
Explanation opens after your attempt
Correct Answer
A. (0)
Concept
This is ((x-6)2=0), so both roots are (6) and (6). Hence \(\alpha-\beta=0\).
Why this answer is correct
The correct answer is A. (0). This is ((x-6)2=0), so both roots are (6) and (6). Hence \(\alpha-\beta=0\).
Exam Tip
यह ((x-6)2=0) है इसलिए दोनों मूल (6) और (6) हैं। अतः \(\alpha-\beta=0\) है।
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