Hard Mathematics Polynomials Class 10 Level 27

यदि \(\alpha=2+\sqrt{5}\) और \(\beta=2-\sqrt{5}\), तो \(\frac{1}{\alpha}+\frac{1}{\beta}\) क्या है?

If \(\alpha=2+\sqrt{5}\) and \(\beta=2-\sqrt{5}\), what is \(\frac{1}{\alpha}+\frac{1}{\beta}\)?

Explanation opens after your attempt
Correct Answer

A. (-4)

Step 1

Concept

\(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}=\frac{4}{4-5}=-4\). Finding sum and product first is easier.

Step 2

Why this answer is correct

The correct answer is A. (-4). \(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}=\frac{4}{4-5}=-4\). Finding sum and product first is easier.

Step 3

Exam Tip

\(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}=\frac{4}{4-5}=-4\)। पहले योग और गुणनफल निकालना आसान रहता है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(\alpha=2+\sqrt{5}\) और \(\beta=2-\sqrt{5}\), तो \(\frac{1}{\alpha}+\frac{1}{\beta}\) क्या है? / If \(\alpha=2+\sqrt{5}\) and \(\beta=2-\sqrt{5}\), what is \(\frac{1}{\alpha}+\frac{1}{\beta}\)?

Correct Answer: A. (-4). Explanation: \(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}=\frac{4}{4-5}=-4\)। पहले योग और गुणनफल निकालना आसान रहता है। / \(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}=\frac{4}{4-5}=-4\). Finding sum and product first is easier.

Which concept should I revise for this Mathematics MCQ?

\(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}=\frac{4}{4-5}=-4\). Finding sum and product first is easier.

What exam hint can help solve this Mathematics question?

\(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}=\frac{4}{4-5}=-4\)। पहले योग और गुणनफल निकालना आसान रहता है।

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