यदि \(a=\sqrt{6}+1\) है तो (a-1) किस प्रकार की संख्या है?
If \(a=\sqrt{6}+1\), what type of number is (a-1)?
Explanation opens after your attempt
Correct Answer
A. अपरिमेय संख्याIrrational number
Concept
\(a-1=\sqrt{6}\), which is irrational. First simplify the expression.
Why this answer is correct
The correct answer is A. अपरिमेय संख्या / Irrational number. \(a-1=\sqrt{6}\), which is irrational. First simplify the expression.
Exam Tip
\(a-1=\sqrt{6}\) है जो अपरिमेय है। पहले अभिव्यक्ति को सरल करें।
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