\(23^\circ45'=\frac{95}{4}^\circ\). In radians it is \(\frac{95}{4}\times\frac{\pi}{180}=\frac{19\pi}{144}\).
Step 2
Why this answer is correct
The correct answer is B. \(\frac{19\pi}{144}\). \(23^\circ45'=\frac{95}{4}^\circ\). In radians it is \(\frac{95}{4}\times\frac{\pi}{180}=\frac{19\pi}{144}\).
Step 3
Exam Tip
\(23^\circ45'=\frac{95}{4}^\circ\) होता है। रेडियन में \(\frac{95}{4}\times\frac{\pi}{180}=\frac{19\pi}{144}\) है।
Mathematics Answer, Explanation and Revision Hints
कोण \(23^\circ45'\) को रेडियन में बदलें। / Convert the angle \(23^\circ45'\) into radians.
Correct Answer: B. \(\frac{19\pi}{144}\). Explanation: \(23^\circ45'=\frac{95}{4}^\circ\) होता है। रेडियन में \(\frac{95}{4}\times\frac{\pi}{180}=\frac{19\pi}{144}\) है। / \(23^\circ45'=\frac{95}{4}^\circ\). In radians it is \(\frac{95}{4}\times\frac{\pi}{180}=\frac{19\pi}{144}\).
Which concept should I revise for this Mathematics MCQ?
\(23^\circ45'=\frac{95}{4}^\circ\). In radians it is \(\frac{95}{4}\times\frac{\pi}{180}=\frac{19\pi}{144}\).
What exam hint can help solve this Mathematics question?
\(23^\circ45'=\frac{95}{4}^\circ\) होता है। रेडियन में \(\frac{95}{4}\times\frac{\pi}{180}=\frac{19\pi}{144}\) है।
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