एक आयत की लंबाई (x+7) और चौड़ाई (x-3) है। क्षेत्रफल (90) हो तो सही समीकरण कौन-सा है?
A rectangle has length (x+7) and breadth (x-3). If its area is (90), which equation is correct?
Explanation opens after your attempt
A. \(x^2+4x-111=0\)
Concept
The area is ((x+7)(x-3)=90). Expanding gives \(x^2+4x-21=90\) and \(x^2+4x-111=0\).
Why this answer is correct
The correct answer is A. \(x^2+4x-111=0\). The area is ((x+7)(x-3)=90). Expanding gives \(x^2+4x-21=90\) and \(x^2+4x-111=0\).
Exam Tip
क्षेत्रफल ((x+7)(x-3)=90) होगा। विस्तार से \(x^2+4x-21=90\) और \(x^2+4x-111=0\) मिलता है।
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