\(\frac{x^4-1}{x^2}\) को सरल करने पर यह बहुपद क्यों नहीं रहेगा?
Why will \(\frac{x^4-1}{x^2}\) not remain a polynomial after simplification?
Explanation opens after your attempt
Correct Answer
A. क्योंकि यह \(x^2-\frac{1}{x^2}\) बनता हैBecause it becomes \(x^2-\frac{1}{x^2}\)
Concept
The simplified form is \(x^2-\frac{1}{x^2}\). Because \(\frac{1}{x^2}=x^{-2}\), it is not a polynomial.
Why this answer is correct
The correct answer is A. क्योंकि यह \(x^2-\frac{1}{x^2}\) बनता है / Because it becomes \(x^2-\frac{1}{x^2}\). The simplified form is \(x^2-\frac{1}{x^2}\). Because \(\frac{1}{x^2}=x^{-2}\), it is not a polynomial.
Exam Tip
सरल रूप \(x^2-\frac{1}{x^2}\) है। \(\frac{1}{x^2}=x^{-2}\) के कारण यह बहुपद नहीं है।
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