\(x^2+\sqrt{x^2}+1\) को सामान्य कक्षा (9) परिभाषा में बहुपद क्यों नहीं माना जाता?

Why is \(x^2+\sqrt{x^2}+1\) not treated as a polynomial under the usual class (9) definition?

Explanation opens after your attempt
Correct Answer

B. क्योंकि चर मूल के अंदर हैBecause the variable is under a root

Step 1

Concept

In class (9), when the variable is under a root, the power is not treated as a valid integer power. So it is not considered a polynomial.

Step 2

Why this answer is correct

The correct answer is B. क्योंकि चर मूल के अंदर है / Because the variable is under a root. In class (9), when the variable is under a root, the power is not treated as a valid integer power. So it is not considered a polynomial.

Step 3

Exam Tip

कक्षा (9) में चर मूल के अंदर हो तो घात पूर्णांक रूप में मान्य नहीं मानी जाती। इसलिए इसे बहुपद नहीं माना जाता।

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Mathematics Answer, Explanation and Revision Hints

\(x^2+\sqrt{x^2}+1\) को सामान्य कक्षा (9) परिभाषा में बहुपद क्यों नहीं माना जाता? / Why is \(x^2+\sqrt{x^2}+1\) not treated as a polynomial under the usual class (9) definition?

Correct Answer: B. क्योंकि चर मूल के अंदर है / Because the variable is under a root. Explanation: कक्षा (9) में चर मूल के अंदर हो तो घात पूर्णांक रूप में मान्य नहीं मानी जाती। इसलिए इसे बहुपद नहीं माना जाता। / In class (9), when the variable is under a root, the power is not treated as a valid integer power. So it is not considered a polynomial.

Which concept should I revise for this Mathematics MCQ?

In class (9), when the variable is under a root, the power is not treated as a valid integer power. So it is not considered a polynomial.

What exam hint can help solve this Mathematics question?

कक्षा (9) में चर मूल के अंदर हो तो घात पूर्णांक रूप में मान्य नहीं मानी जाती। इसलिए इसे बहुपद नहीं माना जाता।