व्यंजक \(\pi x^2+\sqrt{2}x-5\) के बारे में सही कथन कौन सा है?
Which statement is correct about \(\pi x^2+\sqrt{2}x-5\)?
Explanation opens after your attempt
Correct Answer
C. यह बहुपद है क्योंकि गुणांक वास्तविक हैं और घातें मान्य हैंIt is a polynomial because coefficients are real and powers are valid
Concept
\(\pi\) and \(\sqrt{2}\) are real coefficients. The powers of (x) are (2), (1), and (0).
Why this answer is correct
The correct answer is C. यह बहुपद है क्योंकि गुणांक वास्तविक हैं और घातें मान्य हैं / It is a polynomial because coefficients are real and powers are valid. \(\pi\) and \(\sqrt{2}\) are real coefficients. The powers of (x) are (2), (1), and (0).
Exam Tip
\(\pi\) और \(\sqrt{2}\) वास्तविक गुणांक हैं। (x) की घातें (2), (1), और (0) हैं।
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