व्यंजक \(x^2+\frac{x^2-1}{x-1}\) को \(x\neq1\) पर सरल करने से कौन सा बहुपद मिलता है?
Which polynomial is obtained by simplifying \(x^2+\frac{x^2-1}{x-1}\) for \(x\neq1\)?
Explanation opens after your attempt
Correct Answer
A. \(x^2+x+1\)
Concept
\(\frac{x^2-1}{x-1}=x+1\) when \(x\neq1\). So the simplified form is \(x^2+x+1\).
Why this answer is correct
The correct answer is A. \(x^2+x+1\). \(\frac{x^2-1}{x-1}=x+1\) when \(x\neq1\). So the simplified form is \(x^2+x+1\).
Exam Tip
\(\frac{x^2-1}{x-1}=x+1\) जब \(x\neq1\)। इसलिए सरल रूप \(x^2+x+1\) है।
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