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Subjects

Which option is the roster form of T = {x : x is a natural number and 3 ≤ x ≤ 7}?

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Answer and explanation

Correct answer: T = {3, 4, 5, 6, 7}

The governing concept is translating an inclusive bounded condition into roster form. The inequality 3 ≤ x ≤ 7 says that x must be at least 3 and at most 7. Because both inequalities include equality, the endpoints 3 and 7 must be included. The natural numbers satisfying the condition are therefore 3, 4, 5, 6, and 7. Hence T = {3, 4, 5, 6, 7}, making option A correct. Option B leaves out both endpoints, option C omits the upper endpoint 7, and option D omits the lower endpoint 3. No other natural number can satisfy the stated interval. The inclusion signs are the key detail: replacing either ≤ by < would change the corresponding endpoint.

Tags

setsinequalitiesroster formset-builder notationGeneral chapter practiceCommon QuestionscommonMathematics

Frequently asked questions

What is the correct answer to this question?

T = {3, 4, 5, 6, 7}

Why is this the correct answer?

The governing concept is translating an inclusive bounded condition into roster form. The inequality 3 ≤ x ≤ 7 says that x must be at least 3 and at most 7. Because both inequalities include equality, the endpoints 3 and 7 must be included. The natural numbers satisfying the condition are therefore 3, 4, 5, 6, and 7. Hence T = {3, 4, 5, 6, 7}, making option A correct. Option B leaves out both endpoints, option C omits the upper endpoint 7, and option D omits the lower endpoint 3. No other natural number can satisfy the stated interval. The inclusion signs are the key detail: replacing either ≤ by < would change the corresponding endpoint.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Common Questions. Topic: General chapter practice.

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