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Which of the following expressions cannot be factorised into algebraic factors with real coefficients using the identity for the difference of squares?
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Answer and explanation
Correct answer: \(p^2+16q^2\)
\(p^2+16q^2=p^2+(4q)^2\) is a sum of squares, whereas the identity is \(A^2-B^2=(A+B)(A-B)\). In \(9a^2-b^2\), the terms are subtracted. Exam tip: check the sign between the two square terms first.
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What is the correct answer to this question?
\(p^2+16q^2\)
Why is this the correct answer?
\(p^2+16q^2=p^2+(4q)^2\) is a sum of squares, whereas the identity is \(A^2-B^2=(A+B)(A-B)\). In \(9a^2-b^2\), the terms are subtracted. Exam tip: check the sign between the two square terms first.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Exploring Algebraic Identities. Topic: Algebraic identities.
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