Which is the sum of the first (44) natural numbers?
Answer and explanation
Correct answer: 990
The sum of the first \(n\) natural numbers is \(S_n=\frac{n(n+1)}{2}\). Therefore, \(S_{44}=\frac{44\times45}{2}=22\times45=990\). Hence, 990 is correct. A value such as 968 results from not applying the multiplication and division correctly. Exam tip: in \(n(n+1)/2\), always use the number immediately after \(n\).
Frequently asked questions
What is the correct answer to this question?
990
Why is this the correct answer?
The sum of the first \(n\) natural numbers is \(S_n=\frac{n(n+1)}{2}\). Therefore, \(S_{44}=\frac{44\times45}{2}=22\times45=990\). Hence, 990 is correct. A value such as 968 results from not applying the multiplication and division correctly. Exam tip: in \(n(n+1)/2\), always use the number immediately after \(n\).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.
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