समांतर श्रेणी \(5,9,13,17,\ldots\) का सामान्य पद कौन-सा है?

Which is the general term of the arithmetic progression \(5,9,13,17,\ldots\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. \(a_n=4n+1\)

Step 1

Concept

The first term is (5) and the difference is (4), so \(a_n=4n+1\). In exams, use (a_n=a+(n-1)d).

Step 2

Why this answer is correct

The correct answer is B. \(a_n=4n+1\). The first term is (5) and the difference is (4), so \(a_n=4n+1\). In exams, use (a_n=a+(n-1)d).

Step 3

Exam Tip

पहला पद (5) और अंतर (4) है, इसलिए \(a_n=4n+1\) है। परीक्षा में (a_n=a+(n-1)d) लगाएँ।

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Mathematics Answer, Explanation and Revision Hints

समांतर श्रेणी \(5,9,13,17,\ldots\) का सामान्य पद कौन-सा है? / Which is the general term of the arithmetic progression \(5,9,13,17,\ldots\)?

Correct Answer: B. \(a_n=4n+1\). Explanation: पहला पद (5) और अंतर (4) है, इसलिए \(a_n=4n+1\) है। परीक्षा में (a_n=a+(n-1)d) लगाएँ। / The first term is (5) and the difference is (4), so \(a_n=4n+1\). In exams, use (a_n=a+(n-1)d).

Which concept should I revise for this Mathematics MCQ?

The first term is (5) and the difference is (4), so \(a_n=4n+1\). In exams, use (a_n=a+(n-1)d).

What exam hint can help solve this Mathematics question?

पहला पद (5) और अंतर (4) है, इसलिए \(a_n=4n+1\) है। परीक्षा में (a_n=a+(n-1)d) लगाएँ।