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Class 9MathematicsSequences and ProgressionsSum of first n natural numbersEasyLevel 62
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Which is the correct formula for the sum of the first (n) natural numbers?

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Answer and explanation

Correct answer: (\frac{n(n+1)}{2})

The sum of the first (n) natural numbers is (\frac{n(n+1)}{2}). Remembering this formula is the main key for this chapter.

Related tags

SequencesProgressionsNatural-NumbersFormula

Frequently asked questions

What is the correct answer to this question?

(\frac{n(n+1)}{2})

Why is this the correct answer?

The sum of the first (n) natural numbers is (\frac{n(n+1)}{2}). Remembering this formula is the main key for this chapter.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.

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10 more MCQs
  1. 1Let A = {x : x is a natural number and x < 4}. What is A?
  2. 2What will be the 9th term in the sequence (3, −6, 12, −24, …)?
  3. 3If (a=10) and (d=2), what will be the sum of the first (6) terms?
  4. 4If a = 7 and d = 3, what is the sum of the first 6 terms?
  5. 5What is the sum of the first 6 terms of the arithmetic progression (15, 21, 27, 33, ...)?
  6. 6What is the sum of the first (10) natural numbers?
  7. 7Find the sum of the first (20) natural numbers.
  8. 8If \(S_n=\frac{n(n+1)}{2}\), what is \(S_{15}\)?
  9. 9What is the value of (1+2+3+\cdots+25)?
  10. 10Which is the sum of the first (30) natural numbers?
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