अनुक्रम \(6,12,20,30,\ldots\) के लिए सही सामान्य पद कौन-सा है?

Which general term is correct for the sequence \(6,12,20,30,\ldots\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

A. \(a_n=n^2+3n+2\)

Step 1

Concept

\(n^2+3n+2\) gives (6,12,20,30). In exams test options by putting (n=1,2,3).

Step 2

Why this answer is correct

The correct answer is A. \(a_n=n^2+3n+2\). \(n^2+3n+2\) gives (6,12,20,30). In exams test options by putting (n=1,2,3).

Step 3

Exam Tip

\(n^2+3n+2\) से (6,12,20,30) मिलते हैं। परीक्षा में (n=1,2,3) रखकर विकल्प जाँचें।

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Mathematics Answer, Explanation and Revision Hints

अनुक्रम \(6,12,20,30,\ldots\) के लिए सही सामान्य पद कौन-सा है? / Which general term is correct for the sequence \(6,12,20,30,\ldots\)?

Correct Answer: A. \(a_n=n^2+3n+2\). Explanation: \(n^2+3n+2\) से (6,12,20,30) मिलते हैं। परीक्षा में (n=1,2,3) रखकर विकल्प जाँचें। / \(n^2+3n+2\) gives (6,12,20,30). In exams test options by putting (n=1,2,3).

Which concept should I revise for this Mathematics MCQ?

\(n^2+3n+2\) gives (6,12,20,30). In exams test options by putting (n=1,2,3).

What exam hint can help solve this Mathematics question?

\(n^2+3n+2\) से (6,12,20,30) मिलते हैं। परीक्षा में (n=1,2,3) रखकर विकल्प जाँचें।