व्यंजक (\(b^2-1\)x-2+x+4) रेखीय बहुपद कब बनेगा?
When will (\(b^2-1\)x-2+x+4) become a linear polynomial?
Explanation opens after your attempt
Correct Answer
A. जब (b=1) या (b=-1)When (b=1) or (b=-1)
Concept
To become linear, the coefficient of \(x^2\) must be (0). From \(b^2-1=0\), we get \(b=\pm1\).
Why this answer is correct
The correct answer is A. जब (b=1) या (b=-1) / When (b=1) or (b=-1). To become linear, the coefficient of \(x^2\) must be (0). From \(b^2-1=0\), we get \(b=\pm1\).
Exam Tip
रेखीय बनने के लिए \(x^2\) का गुणांक (0) होना चाहिए। \(b^2-1=0\) से \(b=\pm1\) मिलता है।
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