What will be the sum of (1+2+3+\cdots+48)?
Answer and explanation
Correct answer: 1176
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Therefore, \(1+2+\cdots+48=\frac{48\times49}{2}=24\times49=1176\). Hence, option B is correct. Squaring 48 or multiplying 48 and 49 without dividing by 2 gives an incorrect result. Exam tip: for the sum of consecutive natural numbers from 1 to \(n\), use \(\frac{n(n+1)}{2}\).
Frequently asked questions
What is the correct answer to this question?
1176
Why is this the correct answer?
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Therefore, \(1+2+\cdots+48=\frac{48\times49}{2}=24\times49=1176\). Hence, option B is correct. Squaring 48 or multiplying 48 and 49 without dividing by 2 gives an incorrect result. Exam tip: for the sum of consecutive natural numbers from 1 to \(n\), use \(\frac{n(n+1)}{2}\).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.
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