Update

Muft Shiksha™ एक 100% Free Education Portal है 🇮🇳, जिसका उद्देश्य Class 9–12 के हर विद्यार्थी तक High-Quality Education को पूरी तरह मुफ्त पहुँचाना है। 🇮🇳 हम मानते हैं कि अच्छी शिक्षा किसी student की आर्थिक स्थिति पर निर्भर नहीं होनी चाहिए। 🇮🇳 हर विद्यार्थी को वही Quality Study Material, MCQs, Quizzes, Exam Preparation, Concept-Based Learning और Bilingual Support मिलना चाहिए, जो आमतौर पर महंगी Coaching या Premium Platforms में मिलता है। Muft Shiksha™ 🇮🇳 इसी सोच के साथ बनाया गया है

Subjects
0 reads0 ratings0 helpful

What is the value of S_300−S_285, where S_n is the sum of the first n natural numbers?

Advertisement

Answer and explanation

Correct answer: 4395

Since S_n=1+2+...+n, subtracting S_285 from S_300 cancels all terms from 1 through 285. The governing idea is that only the remaining terms 286 through 300 must be added. There are 15 terms, their first and last terms are 286 and 300, and their average is (286+300)/2=293. Therefore the difference is 15×293=4395. Equivalently, S_300−S_285=300×301/2−285×286/2=45150−40755=4395. Thus option B is correct; the other values reflect an incorrect term count or arithmetic error.

Related tags

MathematicsSequencesDifference-Of-SumsArithmetic-SeriesSum Of First N Natural NumbersSequences And ProgressionsClass 9 Mcq

Frequently asked questions

What is the correct answer to this question?

4395

Why is this the correct answer?

Since S_n=1+2+...+n, subtracting S_285 from S_300 cancels all terms from 1 through 285. The governing idea is that only the remaining terms 286 through 300 must be added. There are 15 terms, their first and last terms are 286 and 300, and their average is (286+300)/2=293. Therefore the difference is 15×293=4395. Equivalently, S_300−S_285=300×301/2−285×286/2=45150−40755=4395. Thus option B is correct; the other values reflect an incorrect term count or arithmetic error.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.

Was this question useful?

No ratings yetWrite a review / Rate this question

Student Reviews

No published reviews yet.

Advertisement