What is the value of (1+2+3+\cdots+43)?
Answer and explanation
Correct answer: 946
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Here, \(n=43\), so \(\frac{43\times44}{2}=43\times22=946\). A value such as 936 results from an arithmetic error in multiplication or division. Exam tip: For the sum from \(1\) to \(n\), use \(\frac{n(n+1)}{2}\).
Frequently asked questions
What is the correct answer to this question?
946
Why is this the correct answer?
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Here, \(n=43\), so \(\frac{43\times44}{2}=43\times22=946\). A value such as 936 results from an arithmetic error in multiplication or division. Exam tip: For the sum from \(1\) to \(n\), use \(\frac{n(n+1)}{2}\).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.
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