What is the sum of the first (92) natural numbers?
Answer and explanation
Correct answer: 4278
The sum of the first \(n\) natural numbers is \(S_n=\frac{n(n+1)}{2}\). Therefore, \(S_{92}=\frac{92\times93}{2}=46\times93=4278\). Hence, 4278 is correct. A value such as 4258 can result from a small multiplication or addition error. Exam tip: simplify by dividing the even number, 92, by 2 first.
Frequently asked questions
What is the correct answer to this question?
4278
Why is this the correct answer?
The sum of the first \(n\) natural numbers is \(S_n=\frac{n(n+1)}{2}\). Therefore, \(S_{92}=\frac{92\times93}{2}=46\times93=4278\). Hence, 4278 is correct. A value such as 4258 can result from a small multiplication or addition error. Exam tip: simplify by dividing the even number, 92, by 2 first.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.
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