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What is the sum of the first (6) terms of the arithmetic progression (4,9,14,19,\ldots)?

Answer and explanation

Correct answer: (99)

The direct answer is A: 99. The progression starts with first term a=4 and has common difference d=5 , because 9-4=5, 14-9=5, and 19-14=5. Continuing the pattern gives the first six terms as 4, 9, 14, 19, 24, and 29. Add them carefully: 4+9=13, 13+14=27, 27+19=46, 46+24=70, and 70+29=99. The formula gives the same result: S_n=\frac{n}{2}[2a+(n-1)d]=\frac{6}{2}[2(4)+5(5)]=3(33)=99 . Option A is correct. Option B, 100, is one more than the correct total and may result from an addition error. Option C, 101, is also incorrect because the listed terms total 99. Option D, 105, does not follow from either direct addition or the formula. Always check that six terms, not five or seven, have been used. Memory cue: write the terms first when n is small, then add or verify with the formula.

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SequencesProgressionsArithmetic-ProgressionSum

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