What is the sum of the first (46) natural numbers?
Answer and explanation
Correct answer: 1081
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Substituting \(n=46\), we get \(\frac{46\times47}{2}=23\times47=1081\). Therefore, 1081 is correct. A value such as 1071 can result from an error in multiplication or subtraction. Exam tip: when \(n\) is even, divide it by 2 first to simplify the calculation.
Frequently asked questions
What is the correct answer to this question?
1081
Why is this the correct answer?
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Substituting \(n=46\), we get \(\frac{46\times47}{2}=23\times47=1081\). Therefore, 1081 is correct. A value such as 1071 can result from an error in multiplication or subtraction. Exam tip: when \(n\) is even, divide it by 2 first to simplify the calculation.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.
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