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What is the sum of the first (36) natural numbers?

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Answer and explanation

Correct answer: 666

The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Substituting \(n=36\), we get \(\frac{36\times37}{2}=18\times37=666\). Therefore, 666 is correct. A value such as 676 can result from an arithmetic error. Exam tip: always use the next number, \(n+1\), in the formula.

Related tags

MathematicsSequences And ProgressionsNatural NumbersSum Of N Natural NumbersArithmetic Series

Frequently asked questions

What is the correct answer to this question?

666

Why is this the correct answer?

The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Substituting \(n=36\), we get \(\frac{36\times37}{2}=18\times37=666\). Therefore, 666 is correct. A value such as 676 can result from an arithmetic error. Exam tip: always use the next number, \(n+1\), in the formula.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.

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