What is the sum of the first (132) natural numbers?
Answer and explanation
Correct answer: 8778
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). For \(n=132\), \(\frac{132\times133}{2}=66\times133=8778\). Therefore, 8778 is correct. A value such as 8712 can result from using an incorrect number in place of \(n+1\). Exam tip: Divide the even number 132 by 2 before multiplying.
Frequently asked questions
What is the correct answer to this question?
8778
Why is this the correct answer?
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). For \(n=132\), \(\frac{132\times133}{2}=66\times133=8778\). Therefore, 8778 is correct. A value such as 8712 can result from using an incorrect number in place of \(n+1\). Exam tip: Divide the even number 132 by 2 before multiplying.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.
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