What is the sum of the first (108) natural numbers?
Answer and explanation
Correct answer: 5886
The sum of the first \(n\) natural numbers is \(S_n=\frac{n(n+1)}{2}\). Therefore, \(S_{108}=\frac{108\times109}{2}=54\times109=5886\). Hence, 5886 is correct. A value such as 5866 may result from a small multiplication or addition error, but applying the formula gives 5886. Exam tip: When \(n\) is even, divide \(n\) by 2 before multiplying.
Frequently asked questions
What is the correct answer to this question?
5886
Why is this the correct answer?
The sum of the first \(n\) natural numbers is \(S_n=\frac{n(n+1)}{2}\). Therefore, \(S_{108}=\frac{108\times109}{2}=54\times109=5886\). Hence, 5886 is correct. A value such as 5866 may result from a small multiplication or addition error, but applying the formula gives 5886. Exam tip: When \(n\) is even, divide \(n\) by 2 before multiplying.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.
