What is the sum of natural numbers from (41) to (95)?
Answer and explanation
Correct answer: 3740
There are \(95-41+1=55\) terms from 41 to 95. Hence, the sum is \(\frac{55}{2}(41+95)=\frac{55}{2}\times136=3740\). Therefore, option A is correct. An answer such as 3720 can result from not counting both endpoints correctly. Exam tip: for consecutive integers, always use \(\text{last}-\text{first}+1\) to count the terms.
Frequently asked questions
What is the correct answer to this question?
3740
Why is this the correct answer?
There are \(95-41+1=55\) terms from 41 to 95. Hence, the sum is \(\frac{55}{2}(41+95)=\frac{55}{2}\times136=3740\). Therefore, option A is correct. An answer such as 3720 can result from not counting both endpoints correctly. Exam tip: for consecutive integers, always use \(\text{last}-\text{first}+1\) to count the terms.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.
