What is the sum of natural numbers from (1) to (42)?
Answer and explanation
Correct answer: 903
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Therefore, the sum from \(1\) to \(42\) is \(\frac{42\times43}{2}=21\times43=903\). A value such as \(893\) can result from an error in multiplication or division. Exam tip: for consecutive natural numbers starting from \(1\), directly use \(\frac{n(n+1)}{2}\).
Frequently asked questions
What is the correct answer to this question?
903
Why is this the correct answer?
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Therefore, the sum from \(1\) to \(42\) is \(\frac{42\times43}{2}=21\times43=903\). A value such as \(893\) can result from an error in multiplication or division. Exam tip: for consecutive natural numbers starting from \(1\), directly use \(\frac{n(n+1)}{2}\).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.
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